2x^2-5x+2=20

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Solution for 2x^2-5x+2=20 equation:


Simplifying
2x2 + -5x + 2 = 20

Reorder the terms:
2 + -5x + 2x2 = 20

Solving
2 + -5x + 2x2 = 20

Solving for variable 'x'.

Reorder the terms:
2 + -20 + -5x + 2x2 = 20 + -20

Combine like terms: 2 + -20 = -18
-18 + -5x + 2x2 = 20 + -20

Combine like terms: 20 + -20 = 0
-18 + -5x + 2x2 = 0

Factor a trinomial.
(-2 + -1x)(9 + -2x) = 0

Subproblem 1

Set the factor '(-2 + -1x)' equal to zero and attempt to solve: Simplifying -2 + -1x = 0 Solving -2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1x = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1x = 0 + 2 -1x = 0 + 2 Combine like terms: 0 + 2 = 2 -1x = 2 Divide each side by '-1'. x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(9 + -2x)' equal to zero and attempt to solve: Simplifying 9 + -2x = 0 Solving 9 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -2x = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -2x = 0 + -9 -2x = 0 + -9 Combine like terms: 0 + -9 = -9 -2x = -9 Divide each side by '-2'. x = 4.5 Simplifying x = 4.5

Solution

x = {-2, 4.5}

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